[xquery-talk] (no subject)

[Florent Georges]

fatma helmy wrote:

> for $path in
> ("bookstore/book/title","bookstore/book/price",
> "bookstore/book/author")
> let $leafs :=
>
$bookstore//text()[string-join(ancestor-or-self::element()/node(),'/')
> eq $path]
> return

  [...]

  I don't fully understand how this works.  In place of the following:

    string-join(ancestor-or-self::element()/node(),'/') eq $path

I would have said:

    string-join(ancestor-or-self::element()/name(),'/') eq $path

  Note the 'name()' instead of the 'node()'.  Could you please explain
this a little bit further?

  Thanks.  Regards,

--drkm























	

	
		
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