[xquery-talk] Problem with SubFlowr-Expr
John Snelson
john.snelson at oracle.com
Fri May 11 01:49:51 PDT 2007
This is an operator precedence problem - you need to enclose the two
element constructors in the return expression with parentheses and use a
comma operator to concatenate them into a sequence:
return (
<description>{$a/description/text()}</description>,
<review>This is the Error</review>)
John
florianwendland at freenet.de wrote:
> Hi all,
> I have some wierd problems with a xquery syntax. The query lokks like this:
>
> declare variable $book external;
> declare variable $books external;
>
> <Books>
> {
> for $bid in $book/books/book
> let $b := $books/Import/Row
> return
> <Book>
> <id>{$bid/id/text()}</id>
> <ddd>jj</ddd>
> {
> for $a in $b[xs:integer(./id/text()) eq
> xs:integer($bid/id/text())]
> return
> <description>{$a/description/text()}</description>
> <review>This is the Error</review>
> }
> </Book>
> }
> </Books>
>
>
> The Query could not be parsed, because after the element description, in
> the subflowr, the parser expects an }. I didn't know, what ist wrong
> with it! Can anyone help me? I would be grateful!
>
> Thx
> mfw
> _______________________________________________
> talk at x-query.com
> http://x-query.com/mailman/listinfo/talk
More information about the talk
mailing list