[xquery-talk] Xquery : Sort and get only the first record

Christian Grün christian.gruen at gmail.com
Sun Nov 15 01:35:22 PST 2015


How does your current XQuery expression look like?


On Sun, Nov 15, 2015 at 9:11 AM, sudheshna iyer <sudheshnaiyer at yahoo.com> wrote:
> Thank you all for the reply.
>
> Just need one more modification to this.  In the input if the StartDate is
> blank, then I should consider that as the current job and return the job
> that has blank as the output.
>
> If there are no jobs which have startDate as blank, then it should return
> the recent startdate job (for which we already have the response as shown in
> email chain,,)
>
> For eg, in the below case, response should be the job element with id = 1:
> <?xml version="1.0" encoding="UTF-8"?>
> <Request>
>    <SessionInfo>
>       <uid>qq</uid>
>       <pwd>qq</pwd>
>    </SessionInfo>
>    <Param>
>       <CustomerInfo>
>          <Contact>
>             <Number>123</Number>
>             <Name>aaa bbb</Name>
>             <Jobs>
>                <job>
>                   <Name>Analyst</Name>
>                   <Id>1</Id>
>                   <StartDate></StartDate>
>                   <EndDate>1</EndDate>
>                </job>
>                <job>
>                   <Name>Programmer</Name>
>                   <Id>2</Id>
>                   <StartDate>08-31-2015</StartDate>
>                  <EndDate>2</EndDate>
>                </job>
>             </Jobs>
>          </Contact>
>       </CustomerInfo>
>    </Param>
> </Request>
>
>
>
>
> ________________________________
> From: Ghislain Fourny <g at 28.io>
> To: Ronald Bourret <rpbourret at rpbourret.com>
> Cc: "talk at x-query.com" <talk at x-query.com>; sudheshna iyer
> <sudheshnaiyer at yahoo.com>
> Sent: Tuesday, November 3, 2015 4:51 AM
> Subject: Re: [xquery-talk] Xquery : Sort and get only the first record
>
> Hi Ronald,
>
> You can also use a count clause if you have XQuery 3.0! It makes it easier
> to read. Like so:
>
> for $job in doc('x.xml')//job
> order by xs:date(replace($job/StartDate, "(\d{2})-(\d{2})-(\d{4})",
> "$3-$1-$2")) descending
> count $position
> where $position eq 1
> return $job
>
> I hope it helps.
>
> Kind regards,
> Ghislain
>
>
>
>
> On Mon, Nov 2, 2015 at 6:27 PM, Ronald Bourret <rpbourret at rpbourret.com>
> wrote:
>
> Can't use just use a predicate that returns the first element in the sorted
> sequence? Something like:
>
>   let $seq = for $job in doc('x.xml')//job
>              order by
>                 xs:date(replace($job/StartDate,
>                         "(\d{2})-(\d{2})-(\d{4})", "$3-$1-$2")
>                        ) descending
>              return $job
>   return $seq[1]
>
> (My apologies if the syntax isn't exact. I haven't written an XQuery for
> quite a while.)
>
> -- Ron
>
> On 11/2/2015 5:53 AM, sudheshna iyer wrote:
>
> Thank you very much, Christian. Let me try this..
>
>
>
> ------------------------------------------------------------------------
> *From:* Christian Grün <christian.gruen at gmail.com>
> *To:* sudheshna iyer <sudheshnaiyer at yahoo.com>
> *Cc:* "talk at x-query.com" <talk at x-query.com>
> *Sent:* Sunday, November 1, 2015 4:26 PM
> *Subject:* Re: [xquery-talk] Xquery : Sort and get only the first record
>
> If your XQuery processor supports XQuery Update, this would be one solution:
>
>    copy $xml := doc('x.xml')
>    modify (
>      delete node subsequence(
>        for $job in $xml//job
>        order by xs:date(replace($job/StartDate,
>          "(\d{2})-(\d{2})-(\d{4})", "$3-$1-$2")
>        ) descending
>        return $job
>      , 2)
>    )
>    return $xml
>
> Best,
> Christian
>
>
>
>
> On Sun, Nov 1, 2015 at 8:51 PM, sudheshna iyer <sudheshnaiyer at yahoo.com
> <mailto:sudheshnaiyer at yahoo.com>> wrote:
>  > Team,
>  >
>  > I have an xml which has multiple jobs elements. I want to sort the
> jobs and
>  > want to output only the latest job. Note that <EndDate> can be empty
>  > indicating that it is the current job.
>  >
>  > Basically I want to order by jobs/job/EndDate in descending fashion and
>  > select only the first record..
>  >
>  > How do I do that using xquery?
>  >
>  > Input request:
>  > <?xml version="1.0" encoding="UTF-8"?>
>  > <Request>
>  >  <SessionInfo>
>  >      <uid>qq</uid>
>  >      <pwd>qq</pwd>
>  >  </SessionInfo>
>  >  <Param>
>  >      <CustomerInfo>
>  >        <Contact>
>  >            <Number>123</Number>
>  >            <Name>aaa bbb</Name>
>  >            <Jobs>
>  >              <job>
>  >                  <Name>Analyst</Name>
>  >                  <Id>1</Id>
>  >                  <StartDate>01-01-2015</StartDate>
>  >                  <EndDate>08-30-2015</EndDate>
>  >              </job>
>  >              <job>
>  >                  <Name>Programmer</Name>
>  >                  <Id>2</Id>
>  >                  <StartDate>08-31-2015</StartDate>
>  >                  <EndDate />
>  >              </job>
>  >            </Jobs>
>  >        </Contact>
>  >      </CustomerInfo>
>  >  </Param>
>  > </Request>
>  >
>  > Expected output:
>  >
>  > <?xml version="1.0" encoding="UTF-8"?>
>  > <Request>
>  >  <SessionInfo>
>  >      <uid>qq</uid>
>  >      <pwd>qq</pwd>
>  >  </SessionInfo>
>  >  <Param>
>  >      <CustomerInfo>
>  >        <Contact>
>  >            <Number>123</Number>
>  >            <Name>aaa bbb</Name>
>  >            <Jobs>
>  >              <job>
>  >                  <Name>Programmer</Name>
>  >                  <Id>2</Id>
>  >                  <StartDate>08-31-2015</StartDate>
>  >                  <EndDate/>
>  >              </job>
>  >            </Jobs>
>  >        </Contact>
>  >      </CustomerInfo>
>  >  </Param>
>  > </Request>
>  >
>  > Your help is greatly appreciated.
>
>  >
>  >
>  >
>  >
>  > _______________________________________________
>  > talk at x-query.com <mailto:talk at x-query.com>
>  > http://x-query.com/mailman/listinfo/talk
>
>
>
>
>
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